(x-(2/5))^2=7

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Solution for (x-(2/5))^2=7 equation:


x in (-oo:+oo)

(x-(2/5))^2 = 7 // - 7

(x-(2/5))^2-7 = 0

(x-2/5)^2-7 = 0

(x-2/5)^2-7 = 0

x^2-4/5*x-171/25 = 0

x^2-4/5*x-171/25 = 0

x^2-4/5*x-171/25 = 0

DELTA = (-4/5)^2-(-171/25*1*4)

DELTA = 28

DELTA > 0

x = (28^(1/2)+4/5)/(1*2) or x = (4/5-28^(1/2))/(1*2)

x = (2*7^(1/2)+4/5)/2 or x = (4/5-2*7^(1/2))/2

(x-((4/5-2*7^(1/2))/2))*(x-((2*7^(1/2)+4/5)/2)) = 0

(x-((4/5-2*7^(1/2))/2))*(x-((2*7^(1/2)+4/5)/2)) = 0

( x-((2*7^(1/2)+4/5)/2) )

x-((2*7^(1/2)+4/5)/2) = 0 // + (2*7^(1/2)+4/5)/2

x = (2*7^(1/2)+4/5)/2

( x-((4/5-2*7^(1/2))/2) )

x-((4/5-2*7^(1/2))/2) = 0 // + (4/5-2*7^(1/2))/2

x = (4/5-2*7^(1/2))/2

x in { (2*7^(1/2)+4/5)/2, (4/5-2*7^(1/2))/2 }

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